Sterile solutions of potassium chloride containing 5 mEq/mL are available in 20 mL containers. Calculate the amount, in grams, of potassium chloride in the container.
KCl = 39.1 + 35.5 = 74.6 = molar mass
equivalent mass = 74.6
1 mEq = 0.0746
5 mEq/mL x 20 mL = 100 mEq
100 mEq x 0.0746 g/mEq = ? grams
Why did the potassium chloride go to therapy? Because it couldn't find its "balance"!
But let's get serious now. To calculate the amount of potassium chloride in the 20 mL container, we need to know the molar mass of potassium chloride. The molar mass of KCl is approximately 74.55 g/mol.
First, let's convert 5 mEq to moles. Since 1 mole = 1,000 milliequivalents (mEq), we divide 5 mEq by 1,000 to get 0.005 moles.
Now, we can calculate the amount of potassium chloride in grams by multiplying the moles by the molar mass: 0.005 moles * 74.55 g/mol = 0.37275 grams.
So, there are approximately 0.37275 grams of potassium chloride in the 20 mL container.
To calculate the amount of potassium chloride in the container, we need to know the molecular weight of potassium chloride (KCl).
The molecular weight of potassium (K) is 39.10 g/mol, and the molecular weight of chlorine (Cl) is 35.45 g/mol.
Adding these two values together, we get:
39.10 g/mol (K) + 35.45 g/mol (Cl) = 74.55 g/mol (KCl)
The concentration of the potassium chloride solution is given as 5 mEq/mL, where mEq is milliequivalents.
The milliequivalent weight (mEq) of a substance is the number of milligrams that is equivalent to 1 millimole (1 mmol) of the substance.
Using the definition of mEq, we can calculate the milligrams (mg) of the potassium chloride in one milliliter of the solution as follows:
1 mmol (KCl) = 74.55 mg (KCl)
Therefore, 5 mEq/mL is equal to:
5 mmol (KCl) = 5 mmol (K) + 5 mmol (Cl) = 5 * 74.55 mg (KCl)
To find the amount of potassium chloride in the 20 mL container, we can multiply the concentration (5 mmol/mL) by the volume (20 mL):
5 mmol/mL * 20 mL = 100 mmol
Now we can convert mmol to grams by multiplying by the molar mass:
100 mmol * 74.55 mg (KCl) = 7455 mg (KCl)
Finally, we convert milligrams to grams by dividing by 1000:
7455 mg (KCl) / 1000 = 7.455 g (KCl)
Therefore, there are 7.455 grams of potassium chloride in the 20 mL container.
To calculate the amount of potassium chloride in the container, we need to know the molecular weight of potassium chloride. The molecular weight of potassium (K) is 39.1 g/mol, and the molecular weight of chloride (Cl) is 35.45 g/mol.
To find the molecular weight of potassium chloride (KCl), we add the atomic weights of potassium and chloride:
39.1 g/mol (K) + 35.45 g/mol (Cl) = 74.55 g/mol (KCl)
Now, we can calculate the amount of potassium chloride in each mL of the solution.
Since the concentration is given as 5 mEq/mL, we need to convert it to moles.
One mole of KCl corresponds to 1 mole of potassium ions (K+) and 1 mole of chloride ions (Cl-), so one mole of KCl contains 1 mole of K+ and 1 mole of Cl-.
Since the mEq (milliequivalent) is a measure of the charge, and potassium has a +1 charge and chloride has a -1 charge, we can assume that 1 mEq potassium ion (K+) is equal to 1 mEq chloride ion (Cl-).
Therefore, 5 mEq/mL of potassium chloride is equivalent to 5 mmol/mL.
To convert millimoles (mmol) to moles (mol), we divide by 1000:
5 mmol/mL ÷ 1000 = 0.005 mol/mL
Now, we can multiply the concentration by the volume of the container to find the amount of potassium chloride in the entire 20 mL container.
0.005 mol/mL (concentration) × 20 mL (volume) = 0.1 mol (amount)
Finally, we can use the molecular weight of potassium chloride to convert the amount from moles to grams:
0.1 mol × 74.55 g/mol = 7.455 grams
Therefore, there are approximately 7.455 grams of potassium chloride in the 20 mL container.