A sum of money was to be shared among 3 persons A, B, and C in the ratios 2 : 3 : 8, If C receives $120 more than B, find the sum of money shared.
Let's assume that the common ratio for the three persons is x.
According to the given ratios, the amounts received by A, B, and C can be expressed as 2x, 3x, and 8x, respectively.
We are also given that C receives $120 more than B, so we can write the equation:
8x = 3x + $120
To solve for x, we can subtract 3x from both sides of the equation:
5x = $120
Dividing both sides by 5, we find the value of x:
x = $120 / 5 = $24
Now we can find the amounts received by A, B, and C:
A = 2x = 2 * $24 = $48
B = 3x = 3 * $24 = $72
C = 8x = 8 * $24 = $192
The sum of money shared among A, B, and C is:
$48 + $72 + $192 = $312
Therefore, the sum of money shared among A, B, and C is $312.
To find the sum of money shared, let's take the value of B as x dollars.
According to the given ratios, A will receive 2x dollars and C will receive 8x dollars.
It is also given that C receives $120 more than B. So, we can write the equation:
8x = x + $120
To solve this equation, we can subtract x from both sides:
7x = $120
Now divide both sides by 7:
x = $120 / 7
x ≈ $17.14
So, B receives approximately $17.14.
To find the sum of money shared, we can add the amounts received by A, B, and C:
Sum of money shared = A + B + C = 2x + x + 8x = 11x
Substituting the value of x, we get:
Sum of money shared = 11($17.14) ≈ $188.57
Therefore, the sum of money shared among A, B, and C is approximately $188.57.
c = b+120
a/b = 2/3
b/c = 3/8
solve as usual, then find a+b+c