Atomic symbol of aluminum is written as atomic number(13) atomic mass(27).what information do you get from it

*tell me of its right*:(solution;
atomic no=13
atomic mass=27
no. of electrons=13
no. of protons=13
no. of neutrons=A-Z
no. of neutrons=27-13=14
electronic configuration= *idk*!!!!! help please :(

Well, you need 13 electrons around those 13 protons.

Only two fit in the first ring.
eight more in the second. Now we are at 10
So the last three fit in the third ring.
If the Al atom loses those three electrons in the outer shell
it becomes the Al+3 ion because it now has 3 more positive protons than negative electrons.
That is why for example Aluminum hydroxide is
Al(OH)3

If you want to get into more detail

the first ring holds 2 s electrons (spin+ and spin -)

the second shell holds 2 s electrons and 6 p electrons

we put the remaining 2 s electrons and 1 p electron in the third shell
so 1s2 , 2s2 2p6 , 3s2 3p1

Thankyou so much :)

From the given information, we can determine the following:

Atomic number (Z) = 13: This represents the number of protons in the nucleus of an aluminum atom. Since the atomic number defines the identity of an element, we can conclude that the element is aluminum.

Atomic mass (A) = 27: This represents the sum of protons and neutrons in the nucleus of an aluminum atom. Therefore, the number of neutrons can be calculated by subtracting the atomic number from the atomic mass: A - Z = 27 - 13 = 14. Hence, aluminum has 14 neutrons.

Number of electrons: The number of electrons in a neutral atom is equal to the number of protons. So, aluminum with an atomic number of 13 also has 13 electrons.

Electronic configuration: The electronic configuration of an element refers to how its electrons are distributed across different energy levels or electron shells. Aluminum has the electron configuration [Ne]3s²3p¹, where [Ne] indicates the filled inner electron shell (similar to the noble gas neon). The 3s² signifies that there are a total of 2 electrons in the 3rd energy level (s sublevel), and the 3p¹ represents the presence of 1 electron in the 3rd energy level (p sublevel).

In summary:
- Atomic number (Z) = 13, indicating 13 protons and electrons.
- Atomic mass (A) = 27, implying 14 neutrons (A - Z = 27 - 13 = 14).
- Electronic configuration: [Ne]3s²3p¹.