In an electrical circuit, the current passing through a conductor varies inversely with the resistance. Suppose that the current is 23 A (amperes) the resistance is 10 ohms. What is the current when the resistance is 46 ohms?
Explanation:
In physics this is Ohm's Law, where voltage = current x resistance. Thus, an electrical circuit would be V = 17 x 10, or V = 170 volts. Now, in a real circuit, if the voltage remains constant and the current changes, the resistance will change proportionally. In this case it would be 170 = R x 5, or R = 170/5 = 34 ohms. In the same way, adding resistance to a circuit with a fixed voltage reduces the current through the circuit.
In the case of a simple stated inverse proportional relationship we can simply write the current ratio as 17/5. Then the corresponding changed resistance ratio would be 10/R. The INVERSE is R/10 so the equation is 17/5 = R/10 ; R = 10(17/5) ; R = 170/5 ; R = 34
may it help you :)
RI=k
so you want I such that
46I = 23*10
To find the current when the resistance is 46 ohms, we can use the inverse variation formula:
Current1 * Resistance1 = Current2 * Resistance2
Given:
Current1 = 23 A
Resistance1 = 10 ohms
Resistance2 = 46 ohms
Plugging in these values into the formula:
23 * 10 = Current2 * 46
Simplifying:
230 = Current2 * 46
To find the value of Current2, we need to isolate it. Divide both sides of the equation by 46:
Current2 = 230 / 46
Simplifying further:
Current2 = 5
Therefore, when the resistance is 46 ohms, the current will be 5 A.