How would you prepare 2.5 L of a 0.05 M solution of iron (III) chloride using iron (III) chloride hexahydrate?

Would you use the eqn,
Cinit x Vinit = Cfinal x Vfinal

So I have Cfinal and Vfinal... now what?

from 2.5 L of 0.05 M, how many of moles iron (III) chloride hexahydrate do you need?

Moles = volume x conc

then using number of moles

mass required = number of moles x (RMM of iron (III) chloride hexahydrate)

Then you dissolve this mass in water and make the volume up to 2.5 L.

What does the RMM mean?

Relative Molecular Mass

The RMM stands for Relative Molecular Mass. It is the sum of the atomic masses of all the atoms in a molecule. It is also known as the molecular weight. In the context of your question, the RMM of iron (III) chloride hexahydrate refers to the sum of the atomic masses of all the atoms in one molecule of iron (III) chloride hexahydrate.