71st derivative of the function ๐‘“(๐‘ฅ) = sin^4 x โˆ’ cos^4 x when x =(๐œ‹)/2, So, your challenge is to look for patterns to determine the 71st derivative of the above function evaluated at x =(๐œ‹)/2.

so, did you look for a pattern?

The first thing to note should be that
sin^4 x โˆ’ cos^4 x = sin^2x - cos^2x = -1/2 cos2x
So now it becomes easy
f(1) = -1/2 (-2 sin2x)
(2) = -1/2 (-2^2 cos2x)
f(3) = -1/2 (2^3 sin2x)
f(4) = -1/2 (2^4 cos2x)
now finish it off