If 15.0 mL of 1.2e-4 mol/L HI is added to 26.0 mL of 9.2e-4 mol/L HI, what is the pH of the solution?
M x L = mols.
Calculate mols for solution 1, do the same for solution 2, add mols together and divide by total liters. That will be the new molarity. Then pH = -log(Molarity)
To find the pH of the solution, we first need to calculate the total number of moles of HCl in both solutions.
Step 1: Calculate the moles of HCl in solution 1.
Given:
Volume (V1) = 15.0 mL = 0.015 L
Molarity (M1) = 1.2e-4 mol/L
Using the formula: moles = molarity x volume (in liters)
Moles of HCl in solution 1 = 1.2e-4 mol/L x 0.015 L
Step 2: Calculate the moles of HCl in solution 2.
Given:
Volume (V2) = 26.0 mL = 0.026 L
Molarity (M2) = 9.2e-4 mol/L
Moles of HCl in solution 2 = 9.2e-4 mol/L x 0.026 L
Step 3: Calculate the total moles of HCl.
Total moles = Moles of HCl in solution 1 + Moles of HCl in solution 2
Step 4: Calculate the final molarity.
To calculate the final molarity, divide the total moles by the total volume in liters.
Total volume = V1 + V2
Step 5: Calculate the pH.
Finally, to find the pH of the solution, take the negative logarithm (base 10 logarithm) of the final molarity.
pH = -log(final molarity)
By following these steps and using the provided values, you can determine the pH of the solution.