A stone tied to a string is made to revolve horizontal circle of radius 4m with another speed for 2radia with what tangential velocity will the stone be off the circle if the string cuts
v = R * omega = 4 meters times I suppose but really have no idea if you mean 2 radians / second
PROOFREAD
To find the tangential velocity of the stone when the string is cut, we need to use the concept of centripetal acceleration and the equations of circular motion.
The centripetal acceleration of an object moving in a circular path is given by the formula:
a = (v^2) / r
where a is the centripetal acceleration, v is the tangential velocity, and r is the radius of the circular path.
In this case, we know that the stone is revolving in a horizontal circle of radius 4m and with an angular speed of 2 radians per second. The angular speed can be converted to tangential velocity using the formula:
v = r * ω
where v is the tangential velocity, r is the radius, and ω (omega) is the angular speed.
Let's calculate the tangential velocity:
Given:
Radius of the circle (r) = 4m
Angular speed (ω) = 2 rad/s
Tangential velocity (v) = r * ω
v = 4m * 2 rad/s
v = 8m/s
So, the tangential velocity of the stone when the string is cut will be 8 meters per second.