What is the average ion concentration in a 7.9 mL saturated solution of calcium hydroxide containing calcium chloride (CaCl2)?
To find the average ion concentration in a saturated solution of calcium hydroxide containing calcium chloride, we need to consider the dissociation of these compounds and calculate the concentration of each ion individually.
First, let's write the balanced equations for the dissociation of calcium hydroxide (Ca(OH)2) and calcium chloride (CaCl2):
Ca(OH)2 → Ca²⁺ + 2OH⁻
CaCl2 → Ca²⁺ + 2Cl⁻
Since the concentration of calcium chloride is not provided, we assume it is fully dissociated.
Now, we'll calculate the concentration of each ion using the given volume of the saturated solution (7.9 mL) and the molarities of calcium hydroxide and calcium chloride.
1. Calculate the moles of calcium hydroxide (Ca(OH)2):
Moles of Ca(OH)2 = Molarity of Ca(OH)2 × Volume of solution (L)
2. Calculate the moles of calcium ion (Ca²⁺) from Ca(OH)2:
Moles of Ca²⁺ = Moles of Ca(OH)2
3. Calculate the moles of hydroxide ion (OH⁻) from Ca(OH)2:
Moles of OH⁻ = 2 × Moles of Ca(OH)2
4. Calculate the moles of chloride ion (Cl⁻) from calcium chloride (CaCl2):
Moles of Cl⁻ = 2 × Moles of Ca²⁺
5. Calculate the total moles of ions:
Total moles of ions = Moles of Ca²⁺ + Moles of OH⁻ + Moles of Cl⁻
6. Calculate the concentration of each ion:
Concentration of ions = Total moles of ions / Volume of solution (L)
Now that we have the step-by-step process, we can substitute the given values and calculate the average ion concentration.