The number y is 1 less than 5 times another number x. Their sum is 29.
y = 5 x - 1
y = 29 - x
------------ subtract
0 = 6 x - 30
x = 5
y = 24
d + n = 37 ( so d = 37 - n)
10 d + 5 n = 275
10 (37-n) + 5 n = 275
370 - 10 n + 5 n = 275
95 = 5 n
n = 19
d =37 - 19
To solve this problem, we can set up an equation based on the given information.
Let's assume that the first number is x and the second number is y.
Based on the information given, we know that y is 1 less than 5 times x. So we can write this as an equation:
y = 5x - 1
We also know that the sum of the two numbers is 29. We can write this as another equation:
x + y = 29
Now we have a system of equations to solve. We can use substitution or elimination to find the values of x and y.
Let's use substitution method, where we solve one equation for one variable and substitute it into the other equation.
From the first equation, we can rewrite it as:
x = (y + 1) / 5
Now we substitute this value of x into the second equation:
(y + 1) / 5 + y = 29
Multiply both sides of the equation by 5 to eliminate the fraction:
(y + 1) + 5y = 145
Combine like terms:
6y + 1 = 145
Subtract 1 from both sides:
6y = 144
Divide both sides by 6:
y = 24
Now substitute the value of y back into either equation (let's use the second equation) to find x:
x + 24 = 29
Subtract 24 from both sides:
x = 5
Therefore, the two numbers are x = 5 and y = 24.