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An attractive, scientific visual portraying a chemical reaction between three moles of calcium and three moles of oxygen. The scene includes an obvious imbalance between the elements creating a sense of specific limitation of one substance. The image should predominantly comprise two types of spheres to represent atoms of calcium and oxygen. The calcium atoms should be represented by grey spheres and the oxygen atoms by red spheres. The reaction should be depicted as occurring inside a glass container, with a scientific laboratory as the background. There should be no text in the image.

if 3 mole of of calcium react with 3 mole of oxygen then what

substance is limiting reactant?

2Ca + O2 ==> 2CaO

3 mols Ca will produce how much CaO. That's
3 mols Ca x (2 mols CaO/2 mols Ca) = 3 mols CaO.
How about O2? That's
3 mols O2 x (2 mols CaO/1 mols O2) = 6 mols CaO.
So Ca is the limiting reagent and all of it will be used. O2 is the excess reagent.and some of it will not react.

As he said

As he said the Dr

Well, if 3 moles of calcium walk into a bar and 3 moles of oxygen join them, who's the party pooper? The limiting reactant, of course! So, let's find out which one it is. We'll need to compare the number of moles of each and see which one runs out first.

To determine which substance is the limiting reactant, you need to compare the mole ratio of the reactants to the stoichiometric ratio in the balanced chemical equation.

The balanced chemical equation for the reaction between calcium (Ca) and oxygen (O₂) is:

2Ca + O₂ -> 2CaO

From the balanced equation, you can see that for every 2 moles of calcium, you need 1 mole of oxygen to completely react. Therefore, the stoichiometric ratio of calcium to oxygen is 2:1.

Given that you have 3 moles of calcium and 3 moles of oxygen, it means that both calcium and oxygen are present in equal amounts according to their stoichiometric ratio. Therefore, neither calcium nor oxygen is the limiting reactant in this case.

However, if you had different amounts of calcium and oxygen, you would need to compare their mole ratios with the stoichiometric ratio to determine which one is the limiting reactant. The reactant that is present in the lower amount (with respect to the stoichiometry) would be the limiting reactant, and the other reactant would be in excess.