Chemistry

Consider the titration of 100.0 mL of 0.100 M HC2H3O2 by 0.100 M KOH for the next five questions (Ka for HC2H3O2 = 1.8 x 10-5). Calculate all pH values to two decimal places.

1) Calculate the pH after 0.0 mL of KOH has been added.
2) Calculate the pH after 50.0 mL of KOH has been added.
3) Calculate the pH after 75.0 mL of KOH has been added.
4) Calculate the pH at the equivalence point.
5) Calculate the pH after 150.0 mL of KOH has been added.

1. 👍
2. 👎
3. 👁
1. I think you already know how to do these. What you must do to know how to calculate each is to recognize what you have in the solution. Here is the equation and the millimoles added. Start with 100 mL x 0.100 M = 10 millimoles HC2H3O2.
...................HC2H3O2 + KOH ==> KC2H3O2 + H2O
I.....................10................0.................0................0
C...................-x...............-x...................+x
E....................10-x.............0.....................x
1) Calculate the pH after 0.0 mL of KOH has been added.
2) Calculate the pH after 50.0 mL of KOH has been added.
3) Calculate the pH after 75.0 mL of KOH has been added.
4) Calculate the pH at the equivalence point.
5) Calculate the pH after 150.0 mL of KOH has been added.

1) No KOH is added so the pH is determined by the ionization of the 0.1 M acid.
2) Adding 50 mL KOH addes 50 x 0.1 = 5 mmoles KOH which forms 5 mmoles KC2H3O2. You should recognize this as a buffered solution and solve accordingly.
3) 75.00 mL KOH adds 7.5 mmoles KOH. Just a rerun of (2).
4) The equivalence point. You should know that you have no HC2H3O2 and no NaOH. You have a solution of the salt so the pH will be determined by the hydrolysis of the salt. I've worked some of those problems for you. The pH of NaC2H3O2 solution are in the neighborhood of 8.2 or 8.3 so you will know if you're in the ball park or not.
5). After 150 mL NaOH that's 150 x 0.100 = 15 mmoles NaOH which is more than enough to neutralize all of the acid and have some NaOH left.
The (OH^-) = (NaOH) and pH from there
Post your work if you get stuck on any of these.

1. 👍
2. 👎
👤
DrBob222

Similar Questions

1. Physics

What is the heat in Joules required to raise the temperature of 25 grams of water from 0 °C to 100 °C? What is the heat in calories? Knowing that 4.18 J = 1 calorie and C= 4.18 J/g·°C M=25g C=4.18 J/g Tf=100 Ti=0 Q=25g

2. Chemistry

A 25.0 mL sample of 0.100 M propanoic acid (HC3H5O2, Ka = 1.3 ✕ 10-5) is titrated with 0.100 M KOH solution. Calculate the pH after the addition of the following amounts of KOH. a) 20.0 mL b) 25.0 mL c) 30.0 mL

3. Math (Confused)

A certain economy's consumption function is given by the equation C(x)=0.75x+5 where C(x) is the personal consumption expenditure in billions of dollars and x is the disposable personal income in billions of dollars. Find C(0),

4. Titration

Consider the titration of 100.0 mL of 0.100 M NaOH with 1.00 M HBr. Find the pH at the following volumes of acid added and make a graph of pH versus Va: Va = 0, 1, 5, 9, 9.9, 10, 10.1, and 12 mL.

1. Chemistry

Consider the titration of 100.0 mL of 0.100 M H2NNH2 (Kb = 3.0 10-6) by 0.200 M HNO3. Calculate the pH of the resulting solution after the following volumes of HNO3 have been added. a)0.0 mL b)20.0 mL c)25.0 mL d)40.0 mL e)50.0 mL

2. Chemistry

A 40.0 mL sample of 0.100 M HNO2 is titrated with 0.200 M KOH. Calculate the pH at the equivalence point for the titration of HNO2 and KOH. I got pH= 11.74.

3. Math "Need Help Asap"!

7.)Which proportion can be used to solve the following percent problem? What is 50% of 70% A.)X/70 = 50/100 B.)X/50 = 70/100*** C.)50/70 = X/100 D.)70/X = 50/100 B?

4. Algebra

Suppose you started with 100 bacteria, but they still grew by the same growth factor. Write the function rule for this situation y=100 x 8^x y=100 x 4^x y=8 x 100^x y=4 x 100^x

1. chemistry

pls help. A weak acid HA (pKa = 5.00) was titrated with 1.00 M KOH. The acid solution had a volume of 100.0 mL and a molarity of 0.100 M. Find the pH at the following volumes of base added and make a graph of pH versus Vb: Vb = 0,

2. Chemistry

Calculate the pH for each of the following points in the titration of 50.0 mL of a 2.7 M H3PO3(aq) with 2.7 M KOH(aq). pKa1 = 1.3 and pKa2 = 6.7 a) before addition of any KOH b) after addition of 25.0 mL of KOH c) after addition

3. Math

A physician ordered 1 L of D-10-1/2 NS to infuse over 10 hours. How many grams of Dextrose would the patient receive per hour? I answer like this D10 = 10g/100 ml 1 L= 1000 mL 10 g/100 mL= x/ 1000 mL 100x= 1000x10 x= 10,000/100 x=

4. Math

Mackenzie solved the problem 1.35×1.4. Which shows the correct work to find the product? A. ( 135 × 1 10 ) × ( 14 × 1 10 ) ( 135 × 14 ) × ( 1 10 × 1 10 ) B. ( 135 × 1 100 ) × ( 14 × 1 10 ) ( 135 × 14 ) × ( 1 100 × 1