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The following forces are acting at a point.
1)450N force towards north-east.
2)350N force towards east.
3)250N force at 30º west of north.
4)300N force at 60º south of west.
Find magnitude and direction of the resultant.

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  1. EF = 450 cos 45 + 350 - 250 sin 30 - 300 cos 60
    NF = 450 sin 45 + 0 + 250 cos 30 - 300 sin 60

    magnitude = sqrt (EF^2 + NF^2)
    tan direction East of North = EF/NF
    or if you do math not navigation then
    tan angle North of East = NF/EF

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