The basicity of tetraoxosulphate (iv) acid with 2 explain this statement with an equation show the reaction between the acid and potassium hydroxide
The basicity of H2SO4 is 2 because of the two acid hydrogens in H2SO4.
2KOH + H2SO4 ==> 2H2O + K2SO4
Well, let's talk about the basicity of tetraoxosulphate (IV) acid, or as it's commonly known, sulfuric acid. Sulfuric acid is a strong diprotic acid, meaning it can donate two protons (H+) in a reaction.
When sulfuric acid reacts with potassium hydroxide (KOH), we can write the balanced equation as:
H2SO4 + 2KOH → K2SO4 + 2H2O
So, one molecule of sulfuric acid reacts with two molecules of potassium hydroxide to produce one molecule of potassium sulfate and two molecules of water. This reaction involves the neutralization of the acid and the base, resulting in the formation of a salt (K2SO4) and water (H2O).
Hope that sheds some light on the basicity of sulfuric acid and the reaction with potassium hydroxide! Remember, if chemistry gets too complicated, just add some humor to lighten the mix.
The basicity of an acid refers to the number of hydrogen ions (H+) it can donate per molecule. In the case of tetraoxosulphate (IV) acid, also known as sulfuric acid (H2SO4), it is a diprotic acid, which means it can donate two hydrogen ions per molecule.
When tetraoxosulphate (IV) acid reacts with potassium hydroxide (KOH), a neutralization reaction occurs. The hydrogen ions from the acid react with the hydroxide ions from the base to form water (H2O). The potassium ions (K+) and sulfate ions (SO4^2-) then combine to form potassium sulfate (K2SO4), which is a soluble salt.
The balanced chemical equation for this reaction is:
H2SO4 + 2KOH → K2SO4 + 2H2O
In this equation, the acid (H2SO4) reacts with the base (KOH) to produce the salt (K2SO4) and water (H2O).
To determine the basicity of tetraoxosulphate (IV) acid, you need to identify the number of acidic hydrogen ions (H+) that can be donated by the acid. Tetraoxosulphate (IV) acid, commonly known as sulphuric acid (H2SO4), has two acidic hydrogen ions that can be donated.
The reaction between tetraoxosulphate (IV) acid and potassium hydroxide (KOH) can be represented by the following balanced chemical equation:
H2SO4 + 2KOH → K2SO4 + 2H2O
In this equation, the sulphuric acid (H2SO4) reacts with potassium hydroxide (KOH) to produce potassium sulphate (K2SO4) and water (H2O). The equation indicates that two moles of KOH are required to neutralize one mole of H2SO4, which confirms that tetraoxosulphate (IV) acid is a diprotic acid with a basicity of 2.
Note that the balanced equation represents a neutralization reaction, where an acid reacts with a base to form a salt and water.