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A metal shpere with ane excess of 11 electrons touches an identical metal sphere with an excess of 15 electrons. After the spheres touch, the number of excess electrons on the second sphere is?
My book tells me it is 13, but I don't understand why. If someone could explain, I would appreciate it truly! Thanks!

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asked by Anonymous

  1. The total excess charge is divided equally.

    Total charge=11+15

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    👨‍🏫
    bobpursley

  2. The 2 spheres must have an equal amont do to magn

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    posted by Anonymous

  3. (11+15)/2

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    posted by Anonymous

  5. 26

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    posted by Anonymous

  6. BECAUSE WHEN YOU ADD 16 AND 11 YOU GET 26
    16 + 11 = 26
    THEN AS THE SPEARS TOUCH THEY COME TO EQUILIBRIUM OR EQUALITY.
    SO 26/2
    26 / 2 = 13

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    posted by SONIA

  7. When these two spheres come in contact, the stronger forces of repulsion on the second sphere will move two electrons onto the first sphere. When this occurs, the electrical forces will be in balance and there will be no further net movement of electrons.

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    posted by Bob

  8. 13

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    posted by Anonymous

  10. because when two spheres come in contact, the stronger forces of repulsion on the second sphere will move two electrons onto the first sphere. When this occurs, the electrical forces will be in balance and there will be no further net movement of electrons.

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    posted by Anonymous

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