The diameters of four different types of atoms are given below.
Atom A: 1.35 * 10^-7 mm; Atom B: 1.80 * 10^-7 mm; Atom C: 6.00 * 10^-8 mm; Atom D: 2.50 * 10^-8 mm
What is the order of these atoms from largest to
smallest? (1 point)
A. B;A;C;D
B. C;D;B;A
C. D;C;A;B
D. A;D;B;C
D. A;D;B;C
Why did the atom go to therapy?
Because it had some atomic issues it needed to work through!
To determine the order of atoms from largest to smallest, we need to compare their diameters.
The diameters of the atoms in increasing order are as follows:
Atom D: 2.50 * 10^-8 mm
Atom C: 6.00 * 10^-8 mm
Atom A: 1.35 * 10^-7 mm
Atom B: 1.80 * 10^-7 mm
Therefore, the correct order of the atoms from largest to smallest is:
C; D; A; B
So, the correct answer is option B.
To determine the order of the atoms from largest to smallest, we need to compare their diameters. The atom with the largest diameter is the one with the highest value.
Let's compare the given values:
- Atom A: 1.35 * 10^-7 mm
- Atom B: 1.80 * 10^-7 mm
- Atom C: 6.00 * 10^-8 mm
- Atom D: 2.50 * 10^-8 mm
Looking at the values, we see that:
Atom B > Atom A > Atom C > Atom D
So, the correct order from largest to smallest is: B;A;C;D. This corresponds to choice A.
convert all to use the same power of 10
then just compare the coefficients
If we use 10^-8 for all the numbers, then
A = 13.5 * 10^-8
and so on