A 5.6-kg object is acted on by two forces. One of the forces is 11 N acting toward the east. What is the other force if the acceleration of the object is 1.0 m/ s2 toward the east?

need help :)

m = mass of the object = 5.6 kg

a = object acceleration = 1 m / s²

F1 = the first force = 11 N

F2 = other force

Assume that both forces are on the same line and that both forces are directed to the east.

The total force is:

F = F1 + F2

In this case:

F = F1 + F2

F = 11 + F2

Apply Newton's second law.

F = m a

11 + F2 = 5.6 ∙ 1

11 + F2 = 5.6

Subtract 11 to both sides

F2 = - 5.4 N

The negative value of the second force shows it is towards the west.

So the other force F2 = 5.4 N towards the west.

To find the other force acting on the object, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

F_net = m * a

Given:
Mass of the object (m) = 5.6 kg
Acceleration (a) = 1.0 m/s²
Force 1 (F1) = 11 N (acting toward the east)

To find the other force (Force 2), we can rearrange the equation to solve for Force 2:

F_net = F1 + F2

F2 = F_net - F1

We know that F_net = m * a, so substituting the given values:

F2 = (5.6 kg) * (1.0 m/s²) - 11 N

F2 = 5.6 N - 11 N

F2 = -5.4 N

Therefore, the other force acting on the object is 5.4 N, but in the opposite direction (west).

To find the other force acting on the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula for this law is:

Force = Mass × Acceleration

In this case, we are given the mass of the object as 5.6 kg, and the acceleration as 1.0 m/s^2. We also know that one of the forces acting on the object is 11 N towards the east.

To find the other force, we can substitute the known values into the formula for force:

Force = Mass × Acceleration

Force = 5.6 kg × 1.0 m/s^2

Force = 5.6 N

Therefore, the other force acting on the object is 5.6 N towards the east.