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The sides of a rectangle are in a ratio of 7 : 4. If the perimeter of the rectangle is 176 ft, what is the area of the rectangle?

The area of the rectangle is

sides = 7x

width = 4x
2(7x+4x) = 176
22x = 176
x = 8

sides are 56 and 32

area = length * width

take it from here

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calculated by multiplying the length and width of the rectangle. In this case, since the sides are in a ratio of 7:4, we can assume the length is 7x and the width is 4x, where x is a common factor. To find the value of x, we add up the lengths of all four sides, which gives us: 7x + 7x + 4x + 4x = 22x. Since the perimeter is 176 ft, we equate 22x to 176: 22x = 176. By dividing both sides of the equation by 22, we find that x = 8. Substituting x = 8 back into the values of the length and width, we find the length is 7*8 = 56 ft and the width is 4*8 = 32 ft. Finally, to find the area of the rectangle, we multiply the length and width: Area = 56 ft * 32 ft = 1792 sq ft. Therefore, the area of the rectangle is 1792 square feet.