The acceleration of a gravity on the moon is1.62m/s.if a ball is dropped on the moon from a height of 1.50m,determine the time for the ball to fall to the surface of the moon.
Answer
Answered
To determine the time it takes for the ball to fall to the surface of the moon, we can use the kinematic equation:
s = ut + (1/2)at^2
Where:
s = distance (1.50 m)
u = initial velocity (0 m/s since the ball is dropped)
a = acceleration due to gravity (1.62 m/s^2)
t = time
Rearrange the equation to solve for time (t):
s = (1/2)at^2
Multiply both sides of the equation by 2:
2s = at^2
Divide both sides of the equation by a:
2s / a = t^2
Take the square root of both sides of the equation:
√(2s / a) = t
Now, substitute the values you have:
√(2 * 1.50m / 1.62m/s^2) = t
Calculating the value inside the square root:
√(3 / 1.62) ≈ t
√1.85 ≈ t
t ≈ 1.36 seconds
Therefore, it would take approximately 1.36 seconds for the ball to fall to the surface of the moon.