two students are balancing on a 10 m seesaw . the seesaw is designed so that each side of the seesaw is 5 m long. the student on the left weighs 60 kg and is sitting three meters away from from the fulcrum at the center. the student on the right weighs 45 kg. the seesaw is parallel to the ground. the Mass of the board is evenly distributed so that is center of mass is over the fulcrum. imagine that two students are sitting on the seesaw so that the torque is 0 N*m.which of the following changes will alter the torque of the seesaw?
a. another student stands perfectly on the center of the seesaw.
b. both students move toward the center by one meter.
c. the heavier student moves forward 1 m, while the lighter student moves forward 1.33 m.
Yes, b
initial balance
60 * 3 = 45 x
x = 4
so the student on the right is 4 meters from the fulcrum.
a. There is no torque resulting from more mass at the fulcrum.
b.
60 * (3-1) = 120
45 * (4-1) = 135, the student on the right hits the ground
c,
60 * (3-1) = 120
45 (4-1.33) = 120.15 pretty close to balanced.
So what would it be
Is it b
To determine which changes will alter the torque of the seesaw, we need to consider the conditions for torque balance.
Torque can be calculated using the formula: Torque = Force * Distance
In this case, since we are given that the torque is 0 N*m, we know that the sum of the torques on each side of the fulcrum must be equal.
Let's break down each of the given changes and analyze their effects on the torque:
a. Another student stands perfectly on the center of the seesaw:
In this case, the new student will be equidistant from the fulcrum on both sides, resulting in equal torques and torque balance. Therefore, this change will not alter the torque of the seesaw.
b. Both students move toward the center by one meter:
If both students move towards the center by one meter, the distance between each student and the fulcrum decreases. As torque is directly proportional to the distance, reducing the distance will decrease the torque on each side. This will alter the torque of the seesaw and disrupt the torque balance.
c. The heavier student moves forward 1 m, while the lighter student moves forward 1.33 m:
If the heavier student moves forward by 1 meter, and the lighter student moves forward by 1.33 meters, the distribution of weight will change. The heavier student moving forward will increase the torque on their side, while the lighter student moving forward will decrease the torque on their side. This will result in an imbalance of torque and alter the torque of the seesaw.
So, the changes that will alter the torque of the seesaw are option b (both students move toward the center by one meter) and option c (the heavier student moves forward 1 m, while the lighter student moves forward 1.33 m).