There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the result is a multiple of 3 or a multiple of 4?
1/15
multiples of 3 = 3,6,9,12,15
multiples of 4=4,8,12
7/15
the awnser is 1/15, i just put it in on deltamath and got it right
To find the probability of the spinner landing on a multiple of 3 or a multiple of 4, we need to determine the total number of favorable outcomes and the total number of possible outcomes.
First, let's determine the total number of favorable outcomes. We need to find the multiples of 3 and the multiples of 4 within the given range of numbers (1 to 15).
Multiples of 3: 3, 6, 9, 12, 15 (a total of 5 numbers)
Multiples of 4: 4, 8, 12 (a total of 3 numbers)
However, notice that the number 12 is in both lists. To avoid double counting, we need to subtract 1 from the total count of favorable outcomes.
Total number of favorable outcomes = 5 + 3 - 1 = 7
Next, let's determine the total number of possible outcomes. Since there are 15 equal areas on the spinner, the total number of possible outcomes is simply 15.
Therefore, the probability of the spinner landing on a multiple of 3 or a multiple of 4 is given by:
Probability = (Number of favorable outcomes) / (Number of possible outcomes)
Probability = 7 / 15
To simplify this fraction further, you can divide both the numerator and the denominator by their greatest common divisor (gcd). In this case, the gcd of 7 and 15 is 1, so there is no simplification possible.
So, the final probability is 7/15.
Multiple of 3 = 3, 6, 9, 12, 15
Multiple of 4 = 4, 8, 12
8/15