A boys' age is x years and his father's age is five years as old as his son . what will be the sum of their ages in ten years time. These age is now 17.how old will he be in x years time and what is the sum of his age in x years time and 15 years ago
It would help if you proofread your questions before you posted them.
How can father's age be "five years as old as his son"? Is "he" and "him" father or son?
suppose you meant "five times as old"
In that case, you have
in ten years, the sum will be x+10 + 5x+10
as for what "these age is now 17" means, I have no clue.
Let's break down the information given step-by-step:
1. The boy's age is x years.
2. The father's age is five times as old as his son, so the father's age is 5x years.
3. The current ages of the boy and his father are both 17 years.
To find the age of the boy in 10 years, we will add 10 to x:
Boy's age in 10 years = x + 10
To find the age of the father in 10 years, we will add 10 to 5x:
Father's age in 10 years = 5x + 10
To find the sum of their ages in 10 years, we will add the boy's age in 10 years to the father's age in 10 years:
Sum of their ages in 10 years = (x + 10) + (5x + 10)
Now, let's calculate the age of the boy in x years time:
Boy's age in x years = x + x = 2x
To find the sum of their ages in x years time, we will add the boy's age in x years to the father's age in x years:
Sum of their ages in x years = (2x) + (5x)
Finally, let's calculate the age of the boy 15 years ago:
Boy's age 15 years ago = x - 15
To find the sum of their ages 15 years ago, we will subtract 15 from the boy's age 15 years ago and from the father's age 15 years ago:
Sum of their ages 15 years ago = (x - 15) + (5x - 15)
To find the sum of their ages in ten years time, we need to determine the age of the boy and his father after ten years.
Given that the boy's age is x years and his father's age is five times as old as the son, we can set up an equation as follows:
Father's age = 5 * Son's age
Since the current age of the boy is 17, we substitute x = 17 into the equation:
Father's age = 5 * 17 = 85
After ten years, the boy's age would be 17 + 10 = 27, and the father's age would be 85 + 10 = 95.
Therefore, the sum of their ages in ten years time would be 27 + 95 = 122.
Now let's move on to the second part of the question. We are asked to find the age of the boy in x years time, as well as the sum of their ages in x years time.
To find the boy's age in x years time, we simply add x to his current age:
Boy's age in x years time = 17 + x
As for the sum of their ages in x years time, we need to find the father's age. Since the father's age is five times the son's age, we can write the equation as:
Father's age = 5 * (17 + x)
To find the sum of their ages in x years time, we add the boy's age to the father's age:
Sum of their ages in x years time = (17 + x) + 5 * (17 + x)
Lastly, we are asked about their ages 15 years ago. To determine this, we subtract 15 from the current ages:
Boy's age 15 years ago = 17 - 15 = 2
Father's age 15 years ago = 85 - 15 = 70
Therefore, the boy's age 15 years ago was 2 and the sum of their ages 15 years ago was 2 + 70 = 72.