From a barrel of colored marbles, you randomly select 1 blue, 6 yellow, 7 red, 4 green, and 6 purple marbles.
Find the experimental probability of randomly selecting either a green or a purple marble. (:
The wording of this question makes it impossible.
Perhaps you mean you pick either a green or a purple from a barrel containing:
1 blue, 6 yellow, 7 red, 4 green, and 6 purple marbles
which is 24 in total
prob that it is green = 4/24
prob that it is purple = 6/24
sum = 10/24 = 5/12
tysm!!!!!
To find the experimental probability of randomly selecting either a green or a purple marble, we need to determine the number of favorable outcomes (number of green or purple marbles) and the total number of possible outcomes (total number of marbles in the barrel).
In this case, we have 4 green marbles and 6 purple marbles, so the number of favorable outcomes is 4 + 6 = 10.
The total number of marbles in the barrel is the sum of the number of marbles of each color: 1 blue + 6 yellow + 7 red + 4 green + 6 purple = 24.
Therefore, the experimental probability of randomly selecting either a green or a purple marble is 10/24, which can be simplified to 5/12.
So, the experimental probability of randomly selecting either a green or a purple marble from the barrel is 5/12.