An object is launched from a height 100 m above horizontal ground with a velocity of 30m/s and

an angle of 20o
above the horizontal.
a) Determine the Object’s horizontal displacement upon impact.
b) Maximum vertical displacement at 2seconds after lunched
c) Velocity at 2seconds after lunching

helper guess u cant do it aswell bellend

To answer these questions, we need to break down the motion of the object into its horizontal and vertical components and use the equations of motion.

a) Determine the object's horizontal displacement upon impact:
We can use the equation: horizontal displacement = initial velocity * time
The initial horizontal velocity of the object can be found using trigonometry: horizontal velocity = initial velocity * cos(angle).
Therefore, the horizontal displacement upon impact would be: horizontal displacement = (initial velocity * cos(angle)) * time.

b) Maximum vertical displacement at 2 seconds after launch:
The vertical displacement can be calculated using the equation: vertical displacement = initial vertical velocity * time – (1/2) * acceleration * time^2.
The initial vertical velocity can be found using trigonometry: initial vertical velocity = initial velocity * sin(angle).
In this case, since the object is launched from a height, the initial vertical displacement is 100 m.
So, at 2 seconds after launch, we need to calculate the vertical displacement using the given time.

c) Velocity at 2 seconds after launch:
The horizontal velocity remains constant unless acted upon by an external force, so the horizontal velocity at any time after launch will be the same as the initial horizontal velocity (i.e., horizontal velocity = initial velocity * cos(angle)).
For the vertical component, the velocity can be calculated using the equation: final vertical velocity = initial vertical velocity + acceleration * time.
Using trigonometry, we can find the initial vertical velocity.
At 2 seconds after launch, we can calculate the final vertical velocity using the given time.

By plugging in the values into the above equations, you can find the answers to parts a, b, and c of the problem.

Figure it out on your own. LOL!!!