in a class of 26 students, 14 have a cat and 7 have a dog. There are 5 students who have a cat and dog. What is the probability that a student chosen randomly from the class does not have a dog?
19/26
The number who have one or more animals is 14+7-5 = 16
so, 10 of 26 have no animal
so, 10 + (14-5) have no dog
Oobleck, don't you mean:
The number who have one or more animals is 14+7+5 = 26?
5 have a cat and a dog.
yes, 14 have a cat. Who said they have only a cat?
To find the probability that a student chosen randomly doesn't have a dog, we need to find the number of students who don't have a dog and divide it by the total number of students in the class.
Out of the 26 students, only 7 have a dog, so 19 students do not have a dog. Therefore, the probability that a student chosen randomly from the class does not have a dog is:
19/26
To find the probability that a student chosen randomly from the class does not have a dog, we need to determine the number of students who do not have a dog.
First, we know that there are 26 students in the class. Of these students, 14 have a cat and 7 have a dog. However, 5 students have both a cat and a dog, so we need to adjust our counts accordingly.
Number of students with a cat only = total number of students with a cat - number of students with both a cat and a dog
= 14 - 5
= 9
Now, to find the probability of not having a dog, we divide the number of students without a dog by the total number of students in the class.
Number of students without a dog = total number of students - number of students with a dog
= 26 - 7
= 19
Probability of not having a dog = Number of students without a dog ÷ Total number of students
= 19 ÷ 26
= 0.73 (rounded to two decimal places)
Therefore, the probability that a student chosen randomly from the class does not have a dog is approximately 0.73.
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3:26
Wrong, Skylar! Please don't answer any more questions!
The ones who have only cats do not have a dog.
14/26 = 7/13