1. Questions

Algebra

1- Simplify the radical expression: √250h^4k^5
a) hk√125
b) 5√10h^4k^5
c) 5h^2k^2√10k
d) 25hk√10k **

2- Simplify the radical expression: √21y * 5√49y
a) 5y√1,029
b) 5√1,029y^2
c) 35y√21
d) 35√21y^2 **

3- Simplify the radical expression: √20x^13y^5 / 5xy^7 (this whole fraction is a square root, not just the nominator, this is the same for all the fractions in this question with the √ sign)
a) √4x^12 / y^2
b) 2x^6 / y **
c) 2√x^12 / y^2
d) 2x^6y

4- Simplify the radical expression: 5√7 + 2√175
a) 7√182
b) 15√14
c) 7√175
d) 15√7 **

5- Simplify the radical expression by rationalizing the denominator
√8 / √6x
a) 2√3x / 3x
b) 2√2x / x **
c) √6x / 3x
d) 4√3x / 3x

PLS HELP

  1. 👍
  2. 👎
  3. 👁
Naruto's Ramen

  1. factor out perfect squares.
    #1. √250h^4k^5 = √25*10*h^4*k^4*k = √(25h^4k^4)*10k = 5h^2k^2 √10k
    #2. wrong again. You don't factor them all out
    #3. ok
    #4. ok
    #5. nope. √8*6x = √48x = 4√3x ...

    1. 👍
    2. 👎
    👤
    oobleck

  2. 1- 5h^2k^2 √10k
    2- 35y√21
    3- 2x^6 / y
    4- 15√7
    5- √6x / 3x

    I changed 1, 2, and 5. Are these right? For #2 my original answer was 5√1,029y^2 but I'm pretty sure I got it wrong.

    1. 👍
    2. 👎
    Naruto's Ramen

  4. #1,2 ok
    For #5, √8 / √6x = √48x / 6x = 4√3x / 6x = 2√3x / 3x

    1. 👍
    2. 👎
    👤
    oobleck

  5. Oh I see now.
    Thanks Mr. oobleck!

    1. 👍
    2. 👎
    Naruto's Ramen

Respond to this Question

First Name

Your Response

Similar Questions

  1. math

    simplify this polymomial polynomial 6g + 8k – 9g + 2k my answer -3g+10k

  2. Algebra 1B Radical expressions & data analysis

    1. Simplify 2/√5 A. 2/√5 B. √10 C. √10/5 D. 2√10/5 *** My answer 2. Simplify -11√112 A. -44√7 B. -176 √7 C. -27 √7 D. 4√7 *** My answer 3. Simplify 17√17 -9 √17 A. 8 *** My answer B. 8√17 C. 26√17 D.

  3. Mathmatics

    4.8.1 - Test: Radical Expressions and Equations Unit Test Part 1 Honors Algebra 1 B (CL); 7.20 / 4. Radical Expressions and Data Analysis / 4.8. Radical Expressions and Data Analysis Unit Test Connexus studies! Just went through

  4. Math~Polynomials

    1)6g+8k-9g+2k(1point) 3g+10k -3g+10k*** 17gk 10k-3 2)-4x+6x^2+5x(1point) 7x^3*** 6x^2+9x 6x^2-9x 6x^2+x 3)a^2+5a-3a^2(1point) 5a+2a^2 -2a^2+5a*** -3a^2+6a 5a-3a^2 4)3x^2+8x+7x(1point) 3x^2+15x*** 18x^3 3x^2+1 3x^2-x 5)Find the

  1. algebra

    am I right? 1. Simplify radical expression sqrt 50 5 sqrt ^2*** 2 sqrt ^5 5 sqrt ^10 5 2. Simplify the radical expression sqrt 56x^2 28x 2x sqrt 14*** 2x sqrt 7 sqrt 14x2 3. Simplify the radical expression. sqrt 490y^5w^6 2 sqrt

  2. algebra

    1. simplify the radical expression. √45 5√3 3√5 3√15** 15 2. Simplify the radical expression √180x^2 90x** 6x√5 5x√6 6√5x^2 3. simplify he radical expression √250h^4 k^5 hk√125 5√10h^4 k^5 5h^2 k^2√10k**

  3. Chemistry

    Suppose a runner completes a 10K (10.0 km) road race in 44 minutes and 43 second. What is the runners average speed in miles per hour?

  4. AC DC Circuit fundamentals

    If a 10k ohm and a 5k ohm resister are connected in series across a 12 volt source whats the voltage across the 10k ohm resistor and 5 ohm resistor?

  1. Lesson 1: Polynomials CE 2015 Algebra Readiness (P

    1. 6g + 8k – 9g + 2k a . -3g + 10k . 17gk . 10k – 3 2. -4x + 6.2x + 5x . 7x3 . 6x2 + 9x . 6x2 – 9x . 6x2 + 9x 3. a2 + 5a – 3a2 . 5a + 2a2 . 5a – 2a2 .2a2 + 5a . 5a – 3q2 4. 3x2 + 8x + 7x . 3x2 + 15x . 18x3 . 3x2 +1 3x2

  2. Pre Algebra

    5. (m^2-m-3)+(m-4) A. m^2+m-1 B. m^2+2m-7 C. m^2-7 D. m^2-1 6. (4x^2-2x-1)-(-3x^3+2) A. -3x^3+4x^2-2x+1 B. -3x^3+4x^2-2x-3 C. 3x^3+4x^2-2x+1 D. 3x^3+4x^2-2x-3 9. 100^12/100^8 A. 100^12/8 B. 100^96 C. 100^4*** D. 100^20 16.

  3. algebra

    1 simplify the radical expression. √50 a 5√2 b2√5 c5√10 d5 2 simplify the radical expression √180x^2

  4. power dissipation

    What is the power dissipated by resistor R1 of the following circuit: two batteries in series (with values V1 = 20 volts and V2 = 20 volts) connected across three resistors in series with values R1 = 10k, R2 = 10k, and R3 = 20k im

You can view more similar questions or ask a new question.