Question

find the derivative of the functions F(x)= tan^2(x) and G(x) = sec^2(x).... based on your calculations what can you say about F(x) - G(x)

I found F'x =2 secx^2tanx
G'(x)= 2secx^2tanx then when subtracted they equal zero, is there more explanation for this?

Answer 1

yes.

sec^2x - tan^2x = 1
so of course the derivative is zero.