At what height above the ground must a body of mass 10kg be situated in order to have a potential energy equal in value to the kinetic energy passed by another body of mass 10kg moving with a velocity of 10ms-1(g=9.8ms-2).
Can it, @Josh.
PE = mgh
KE = 1/2 mv^2
so, just solve
10*9.81*h = 1/2 * 10 * 10^2
and that's "possessed," not "passed."
To find the height at which a body of mass 10kg must be situated in order to have potential energy equal to the kinetic energy of another body, we can use the equations for potential energy and kinetic energy.
The potential energy of an object of mass m at a height h above the ground is given by the equation:
Potential energy = mass * gravitational acceleration * height
PE = m * g * h
The kinetic energy of an object of mass m moving with a velocity v is given by the equation:
Kinetic energy = (1/2) * mass * velocity^2
KE = (1/2) * m * v^2
Given that the mass of both bodies is 10kg and the velocity of the moving body is 10m/s, we can equate the potential energy to the kinetic energy:
m * g * h = (1/2) * m * v^2
Now, let's substitute the given values:
10kg * 9.8m/s^2 * h = (1/2) * 10kg * (10m/s)^2
2 * 9.8 * h = 50
19.6h = 50
To solve for h, we divide both sides of the equation by 19.6:
h = 50 / 19.6
h ≈ 2.55
Therefore, the body must be situated at a height of approximately 2.55 meters above the ground to have a potential energy equal to the kinetic energy of the other body.