The drawing is composed of a rectangle and a semicircle. Find the area of the figure to the nearest unit the height is ten and the length is 22
You done yet... lol
I assume you know that the areas are
rectangle: length * width
semi-circle: 1/2 πr^2
so look at your diagram and plug in the numbers!
The answer is 410 cm^2.
You find the area of the half circle by multiplying the radius, which is 22 divided by 2, so it's 11^2 x 3.14 = 379.94 or 380. Divide 380 by 2 which is 190.
Now, find the area of the rectangle. Which is 10 x 22 = 220.
Now, add 220 + 190 = 410 cm^2.
You're welcome. =)
What is this
What is what
it was wron
To find the area of the figure, we first need to calculate the area of the rectangle and then the area of the semicircle. Finally, we can add these two areas together to get the total area.
1. Area of the rectangle:
The formula for calculating the area of a rectangle is A = length × width.
In this case, the length is given as 22 and the height as 10. Therefore, the area of the rectangle is A = 22 × 10 = 220 square units.
2. Area of the semicircle:
The formula for calculating the area of a semicircle is A = (π × r^2) / 2, where r is the radius.
In this case, the diameter of the semicircle is the same as the height of the rectangle (10 units). So, the radius is half of the diameter, which is 10 / 2 = 5 units.
Plugging this value into the formula, we get A = (π × 5^2) / 2 ≈ 39.27 square units (rounded to two decimal places).
3. Total area of the figure:
To find the total area, we add the area of the rectangle and the area of the semicircle together:
220 + 39.27 ≈ 259.27 square units (rounded to two decimal places).
Therefore, the area of the figure, to the nearest unit, is 259 square units.