An elementary school bus comes at 8:15 am every morning to pick up children in a neighborhood. The probability that the bus will be late is 0.19 and the probability that the bus will be early is 0.02.
What is the probability that the bus will arrive early next two days?
What is the probability that the bus will arrive on time next two days?
In two or more complete sentences, explain your calculations for parts A and B. In your explanation, include their similarities and differences.
0.02 * 0.02
prob that bus is either too early or late = 0.21
so probability within desired time = 1 - 0.21 = 0.79
so for 2 days 0.79*0.79
You can write about it :)
To calculate the probability that the bus will arrive early on both days, we can multiply the individual probabilities. Since these events are independent, the probability of both events occurring can be found by multiplying the probabilities together.
For the first day, the probability of the bus arriving early is 0.02. Thus, the probability of the bus arriving early on the next day is also 0.02. So, the probability that the bus will arrive early on both days is 0.02 * 0.02 = 0.0004.
To calculate the probability that the bus will arrive on time on both days, we also need to multiply the individual probabilities. In this case, the probability of the bus arriving on time is 1 - (0.19 + 0.02) = 0.79. Therefore, the probability of the bus arriving on time on the next day is also 0.79. So, the probability that the bus will arrive on time on both days is 0.79 * 0.79 = 0.6241.
Both calculations involve multiplying the individual probabilities together. However, the probabilities used are different. For part A, we used the probability that the bus will be early, which is 0.02. For part B, we used the probability that the bus will be on time, which is 0.79. Therefore, the calculations for parts A and B are based on different probabilities, resulting in different outcomes.