# Algebra

Use the Quadratic Formula to solve the equation. (Enter your answers as a comma-separated list.) 13x^2 + 1= -10x

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1. Hmm lets see... I cant write the answers in because it will just say letters 😢 but if you want the answers go to symbolab you can type that in their :D have a nice day and stay safe

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2. First, put it into standard form
13x^2 + 1= -10x
13x^2 + 10x + 1 = 0
then apply the formula, and you get
x = (-10±√(10^2-4*13*1))/(2*13)

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oobleck
3. yeah kind of like that

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4. 13x² + 10 x + 1 = 0

a = 13 , b = 10 , c = 1

x½ = [ - b ± √ ( b² - 4 a c ) ] / 2 a

x½ = [ - 10 ± √ ( 10² - 4 ∙ 13 ∙ 1 ) ] / 2 ∙ 13 = [ - 10 ± √ ( 100 - 52 ) ] / 26 =

( - 10 ± √48 ) / 26 = [ - 10 ± √ (16 ∙ 3 ) ] / 26 = ( - 10 ± √16 ∙ √3 ) / 26 =

( - 10 ± 4√3 ) / 26 = ( - 2 ∙ 5 ± 2 ∙ 2 √3 ) / 26 = 2 ( - 5 ± 2 √3 ) / 2 ∙ 13

x½ = ( - 5 ± 2√3 ) / 13

x1 = ( - 5 - 2√3 ) / 13 = - 5 / 13 - 2√3 / 13

x 2 = ( - 5 + 2√3 ) / 13 = - 5 / 13 + 2√3 / 13

The solutions are:

- 5 / 13 - 2√3 / 13 , - 5 / 13 + 2√3 / 13

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