mathematics

A binary operation ∆ defined on the R of real numbers by a∆b=A square-2ab+bsquare where a,bER find (a)R such that 2∆(-5)=√8. (b) (x+1)∆x out of x, x is not equal to 0.

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  1. Solve for this

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  2. a∆b = a^2-2ab+b^2 = (a-b)^2

    (a) Huh? 2∆(-5) = (2+5)^2 = 49
    It cannot be √8
    What does R have to do with it?

    (b) (x+1)∆x = (x+1-x)^2 = 1
    what does "out of x" mean?

    I think you have garbled the question.

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    oobleck

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