At a busy street corner the sound level is said to be 75bB.what is the intensity of sound there?

I want a solution to the question

in a few seconds, a web search will provide a table of sound levels and intensities.

To determine the intensity of sound at a given sound level, you can use the formula:

Intensity (I) = 10^(L/10)

where L is the sound level in decibels (dB).

In this case, the given sound level is 75 dB. So, to find the intensity of sound at the busy street corner, you can substitute this value into the formula:

I = 10^(75/10)

Let's calculate it step by step:

Step 1: Divide the sound level by 10
L/10 = 75/10 = 7.5

Step 2: Raise 10 to the power of the value obtained in Step 1
10^(L/10) = 10^(7.5)

Now, you can use a calculator or a programming language to calculate the result. For example, in Python, you can write:

import math
I = math.pow(10, 7.5)

The result is approximately 31622.7766.

Therefore, the intensity of sound at the busy street corner is approximately 31622.7766 units (please note that the unit is not specified in the question).