200 students in a school. 58 play football, 40 play basketball and 8 play both.
What is the probability that a student plays basketball but not football?
Use a Venn diagram to show that there are 32 students playing only basketball.
(Did you notice that 110 students do not play either of the 2 sports?)
Prob(only basketball) = 32/200 = 4/25
To find the probability that a student plays basketball but not football, we need to subtract the number of students who play both sports from the total number of students who play basketball.
Total number of students who play basketball = 40
Number of students who play both football and basketball = 8
Therefore, the number of students who play basketball but not football = 40 - 8 = 32.
Probability that a student plays basketball but not football = Number of students who play basketball but not football / Total number of students
Probability = 32 / 200 = 0.16
So, the probability that a student plays basketball but not football is 0.16 or 16%.
To find the probability that a student plays basketball but not football, we need to determine the number of students who play basketball only and divide it by the total number of students.
First, we calculate the number of students who play both basketball and football by subtracting the number of students who play both (8) from the number who play football (58).
58 - 8 = 50 students play football only.
Next, we calculate the number of students who play basketball only by subtracting the number of students who play both (8) from the number who play basketball (40).
40 - 8 = 32 students play basketball only.
Now, we can calculate the probability of a student playing basketball but not football by dividing the number of students who play basketball only (32) by the total number of students (200).
Probability = Number of students playing basketball only / Total number of students
Probability = 32 / 200
Probability = 0.16
Therefore, the probability that a student plays basketball but not football is 0.16 or 16%.