Bobby has a bag of marbles.
In his bag of marbles are:
• 8 Red Marbles
• 7 Blue Marbles
• 3 Yellow Marbles
• 9 Green Marbles
If Bobby randomly choses one marble from the bag what is
the probability that he will choose a green marble?
To find the probability of selecting a green marble, we need to determine the total number of marbles in the bag and the number of green marbles.
The total number of marbles in the bag is the sum of the red, blue, yellow, and green marbles:
Total number of marbles = 8 (Red) + 7 (Blue) + 3 (Yellow) + 9 (Green) = 27
The number of green marbles is 9.
Therefore, the probability of randomly selecting a green marble is:
Probability = Number of green marbles / Total number of marbles
Probability = 9 / 27
Probability = 1/3
So, the probability of Bobby choosing a green marble is 1/3.
To find the probability of choosing a green marble, we need to divide the number of favorable outcomes (choosing a green marble) by the total number of possible outcomes (choosing any marble from the bag).
In this case, the number of favorable outcomes is the number of green marbles, which is 9. The total number of possible outcomes is the sum of all the marbles, which is 8 + 7 + 3 + 9 = 27.
So, the probability of Bobby choosing a green marble is 9/27.
Simplifying the fraction, we get:
Probability = 9 ÷ 27 = 1/3
Therefore, the probability that Bobby will choose a green marble is 1/3.