12.5g of zinc tioxocarbonate (iv), znco3 were heated very strongly to a constant mass and the residue heated with excess hydrochloric acid Hcl calculate the mass of zinc that would be obtained
To calculate the mass of zinc that would be obtained, we need to understand the chemical reaction involved and use stoichiometry to determine the mass.
The given compound, zinc tioxocarbonate (IV) ZnCO3, can be represented by the equation:
ZnCO3(s) → ZnO(s) + CO2(g)
This means that when heated, zinc tioxocarbonate decomposes to form zinc oxide (ZnO) and carbon dioxide (CO2).
To find the mass of zinc, we need to calculate the molar mass of zinc tioxocarbonate (IV). The molar mass of ZnCO3 is 125.38 g/mol. This mass is made up of the molar mass of zinc (65.38 g/mol), carbon (12.01 g/mol), and oxygen (16.00 g/mol), taking into account the number of atoms.
Next, we need to find the moles of zinc tioxocarbonate (IV) present in the given mass of 12.5 g. To do this, we divide the mass by the molar mass:
Moles of ZnCO3 = 12.5 g / 125.38 g/mol
Now, we need to use the stoichiometry of the balanced equation to determine the ratio of moles of ZnCO3 to moles of zinc. From the equation, we can see that for every 1 mole of ZnCO3, 1 mole of Zn is produced.
So, the moles of zinc obtained will be the same as the moles of zinc tioxocarbonate (IV):
Moles of Zn = Moles of ZnCO3
Finally, we can calculate the mass of zinc obtained by multiplying the moles of zinc by its molar mass:
Mass of Zn = Moles of Zn × Molar mass of Zn
Substituting the values, we have:
Mass of Zn = Moles of Zn × 65.38 g/mol
Thus, to calculate the mass of zinc obtained, you need to find the moles of zinc tioxocarbonate (IV) using its molar mass and the given mass, and then multiply it by the molar mass of zinc.
I need the assignment right now pls
I should point out that the problem asks for the amount of Zn from these reactions; however, Zn is not produced anywhere. Second, the response by Helper gives the grams of ZnCl2 produced, which is not the question, but undoubtedly is what the student intended to ask and 13.6 g ZnCl2 is correct. Finally, the statement "Thus you will obtain approximately 0.2 mols ZnCl2 is not correct because you didn't start with 0.2 mol ZnCO3.
ZnCO3 ==> ZnO + CO2, then
ZnO + 2HCl ==> ZnCl2 + H2O
mols Zn = grams/atomic mass = 12.5/65.4 = about 0.2 but that's just an estimate. You need to recalculate all of these numbers for a better answer to this question. Looking at the equation 1 mol ZnCO3 produces 1 mol ZnO and 1 mol ZnO produces 1 mol ZnCl2; therefore, 1 mol Zn will produce 1 mol ZnCl2. Thus you will obtain approximately 0.2 mols ZnCl2.
Then grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?.
12.5/125*136
0.1*136=13.6 answer