If zeroes of p(x)=2x²- 7x+k are reciprocal of each other, then find the value of k
I'm fat
To find the value of k when the zeros of the polynomial p(x) = 2x² - 7x + k are reciprocals of each other, we need to apply the properties of reciprocal zeros.
Let's assume the zeros are a and 1/a, where a is a non-zero real number.
The product of the zeros is given by a * (1/a) = 1.
From the polynomial equation, we know that the product of the zeros is also equal to the constant term divided by the coefficient of the highest power of x, which in this case is k/2.
So, k/2 = 1.
Multiplying both sides of the equation by 2, we get:
k = 2 * 1 = 2.
Therefore, the value of k is 2.
Very Very Bad Of You
The product of the roots is k/2
Since r * 1/r = 1, k = 2