Find the resultant of two forces of 4N and 5N if they are incline perpendicular to each other
x force = 4
y force = 5
|F|^2 = 16 + 25
|F| = sqrt ( 41 ) = 6.4 Newtons
tan theta= 5/4 = 1.25
theta = 51.3 degrees above x axis
To find the resultant of two forces that are inclined perpendicular to each other, you can use the Pythagorean theorem.
The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the two forces of 4N and 5N can be considered as the sides of a right-angled triangle, with the resultant force being the hypotenuse.
So, you can use the following formula to find the resultant force:
Resultant force = √(Force1^2 + Force2^2)
Plugging in the values, we have:
Resultant force = √(4^2 + 5^2)
= √(16 + 25)
= √41
≈ 6.40N
Therefore, the resultant of the two forces of 4N and 5N inclined perpendicular to each other is approximately 6.40N.