A sports team is building a new stadium on a rectangular lot of land. If the lot measures 8x by 12x and the sports field will be 2x by 4x, how much of the lot will be left over to build bleachers on?

a. 104x^2
b. 28x^2
c. 96x^2
d. 88x^2

well, just find

(8x)(12x) - (2x)(4x)
= ....

8x (12x -1 x) = 8x*11x = 88x^2

To find out how much of the lot will be left over to build bleachers on, we first need to find the area of the lot and the area of the sports field.

The area of a rectangular lot is found by multiplying its length by its width. Given that the lot measures 8x by 12x, the area of the lot is:

Area of lot = length * width
= 8x * 12x
= 96x^2

Next, we need to find the area of the sports field. Given that the sports field will be 2x by 4x, the area of the sports field is:

Area of sports field = length * width
= 2x * 4x
= 8x^2

To find the area left over to build bleachers on, we subtract the area of the sports field from the area of the lot:

Area left over = Area of lot - Area of sports field
= 96x^2 - 8x^2
= 88x^2

Therefore, the answer is d. 88x^2.