Argentite (Ag2S) is one of the common ores of silver. If you would like to get 26.2 moles of silver, how many kilograms of Ag2S are needed?
___________ kg Ag2S. Do NOT enter the unit and report your final answer with 3 SFs.
I actually don't know how to do this just being honest. Could anyone help me?
There are 2 mols of Ag in every mol of Ag2S
26.2 mols of Ag is therefore 13.1 mols of Ag2S
a mol of Ag2S is 2*107.87 + 32.06 = 247.8 grams
we need 13.1 *247.8 = 3246.2 grams
= 3.25 kg
there are 2 mols of Ag in every mol of Ag2 whatever
because
there are 2 Ag atoms in every molecule of Ag2 whatever
I am so sorry there's a mistake on the question instead of the 26.2 it should be 21.9
so just do what I did with the new number :)
Could you explain how did you get 13.1 mols? I am still having hard time with this lol
To find out how many kilograms of Ag2S are needed to obtain 26.2 moles of silver, we need to use the molar ratio between Ag2S and Ag. The molar ratio can be determined from the balanced chemical equation for the reaction between Ag2S and Ag.
The balanced chemical equation is:
2Ag2S + 3O2 → 2Ag + 2SO2
From the equation, we can see that 2 moles of Ag2S react to form 2 moles of Ag. This means that the molar ratio between Ag2S and Ag is 2:2, which simplifies to 1:1.
So, for every mole of Ag2S, we obtain one mole of Ag.
To convert moles of Ag to moles of Ag2S, we need to use the inverse of the molar ratio, which is 1:1. In other words, for every mole of Ag, we need one mole of Ag2S.
Given that you want to obtain 26.2 moles of Ag, we require the same number of moles of Ag2S. Therefore, you need 26.2 moles of Ag2S.
Next, we need to convert moles of Ag2S to kilograms. To do this, we need the molar mass of Ag2S.
The molar mass of Ag2S is calculated as follows:
Molar mass of Ag = 107.87 g/mol
Molar mass of S = 32.07 g/mol
Molar mass of Ag2S = (2 * Molar mass of Ag) + Molar mass of S
= (2 * 107.87 g/mol) + 32.07 g/mol
= 216.74 g/mol + 32.07 g/mol
= 248.81 g/mol
Now, we can convert moles of Ag2S to kilograms using the molar mass and the following conversion factor:
1 mol Ag2S = 248.81 g Ag2S
To find the mass of Ag2S in kilograms, we can use the following calculation:
Mass (kg) = (moles of Ag2S) * (molar mass of Ag2S in g/mol) / 1000
Mass (kg) = (26.2 mol) * (248.81 g/mol) / 1000
Calculating this expression gives us the answer in kilograms.
The final answer with 3 significant figures is _______ kg Ag2S. You can use the equation provided to calculate the result.