A sports team is building a new stadium on a rectangular lot of land. If the lot measures 5x by 10x and the sports field will be 4x by 7x, how much of the lot will be left over to build bleachers on?
To find out how much of the lot will be left over to build bleachers on, we need to calculate the area of the lot and subtract the area of the sports field.
The area of a rectangle is found by multiplying its length by its width.
The lot measures 5x by 10x, so its area would be 5x * 10x = 50x^2.
The sports field measures 4x by 7x, so its area would be 4x * 7x = 28x^2.
To determine how much of the lot is left over, we subtract the area of the sports field from the area of the lot:
50x^2 - 28x^2 = 22x^2.
So, there will be 22x^2 of the lot left over to build bleachers on.
well, the area of the whole lot is 5 x * 10 x = 50 x^2
and the area of the playing field is 4 x * 7 x = 28 x^2
The difference is the space left for watching the game
50 - 28 = 22 x^2