Use your calculator to find the length of the arc from t = 0 to t = 3 of x = 2t + 1, y = t2 - 1.

Type your answer in the space below and give 3 decimal places. If your answer is less than 1, place a leading "0" before the decimal point (ex: 0.482). (10 points)

s = ∫[0,3] √((2)^2 + (2t)^2) dt = ∫[0,3] 2√(t^2+1) dt

= 3√10 + sinh-1(3)