The 10th term of an arithmetic progression is 68 and the common difference is 7 find first term of a sequence
How to solve it
Thanks a lot
d=7
a_10 = a+9d
so
a+63 = 68
a = 5
how did a is 5 a=5
The 10term of of arithmetic progression is 68 and the common difference is 7,find the first term born the sequence
The first term of a linear sequence is 5 and the common difference is -3,find the 15th term of the sequence
To find the first term of an arithmetic progression (AP), we need to know the common difference and one of the terms.
Given:
Common difference (d) = 7
10th term (T10) = 68
To find the first term (T1), we can use the formula for the nth term of an AP:
Tn = T1 + (n - 1) * d
Substituting the given values:
T10 = T1 + (10 - 1) * 7
68 = T1 + 9 * 7
68 = T1 + 63
Now, let's isolate T1 by subtracting 63 from both sides:
68 - 63 = T1
5 = T1
Therefore, the first term of the sequence is 5.