The sum of two numbers is 46. The larger number is twice the smaller number +10. Find both numbers. Do not solve!
Find both numbers. Do not solve! ?????
So what do you want?
let the smaller be x
then the larger is 2x+10
x + 2x+10 = 46
N = 2n + 10
n + 2n + 10 = 46
To find both numbers, we can set up a system of equations based on the given information.
Let's call the smaller number "x" and the larger number "y."
From the first statement, we are told that the sum of the two numbers is 46. We can write this as an equation: x + y = 46.
From the second statement, we are told that the larger number (y) is twice the smaller number (x), plus 10. We can write this as an equation: y = 2x + 10.
So, the two equations we have are:
1) x + y = 46
2) y = 2x + 10
Now, to find both numbers, we would need to solve this system of equations. We can do this using various methods like substitution or elimination.
But it seems like you are asking for an explanation without solving it, so I won't provide the actual numerical solution here. However, I explained the process of setting up the equations and you can use any method you prefer to solve them and find the values of x and y.