A current of 45A is pass through a solution of gold salt for 1hours 45minute. Calculate Mass of gold deposited, b) number of mole deposited c) if the same current is used find the time taken for 5.5g to be deposited
no
No
To calculate the mass of gold deposited, we need to use Faraday's law of electrolysis, which states that the amount of substance deposited at an electrode is directly proportional to the quantity of electricity passing through the circuit.
The formula to calculate the mass of a substance deposited during electrolysis is:
Mass (g) = (Current (A) x Time (s) x Molar mass (g/mol)) / (Charge of 1 mole of electrons (C/mol))
a) Calculating the mass of gold deposited:
1 hour 45 minutes is equal to 1 hour + 45 minutes = 60 minutes + 45 minutes = 105 minutes.
Converting 105 minutes to seconds: 105 minutes x 60 seconds/minute = 6300 seconds.
The molar mass of gold (Au) is approximately 197 g/mol.
The charge of 1 mole of electrons can be found using the equation:
(1 F = 96485 C/mol) where F is the Faraday constant.
The equation becomes:
Mass (g) = (Current (A) x Time (s) x Molar mass (g/mol)) / (Charge of 1 mole of electrons (C/mol))
Mass (g) = (45 A x 6300 s x 197 g/mol) / (96485 C/mol)
Now we can plug in the values and calculate:
Mass (g) = (283500 A.s.g) / 96485 C
b) To calculate the number of moles deposited, we use the formula:
Moles = Mass (g) / Molar mass (g/mol)
Moles = Mass (g) / 197 g/mol
c) To find the time taken to deposit 5.5 g of gold, we rearrange the formula:
Time (s) = (Mass (g) x Charge of 1 mole of electrons (C/mol)) / (Current (A) x Molar mass (g/mol))
Time (s) = (5.5 g x 96485 C/mol) / (45 A x 197 g/mol)
Now you can plug in the values and calculate the time taken in seconds.
Remember to always double-check your units and conversions for accuracy.
No
No
No
coulombs = amperes x seconds
coulombs = 45 x 1.75 hr x (60 min/hr) x (60 sec/min) = 283,500
96,485 coulombs will deposit 1/3 of a mol of Au from Au^3+ solutions.
So 1/3 mole x (283,500/96,485) = ? mols Au deposited.
You have all of the info needed. Can you do the last part?