2KClO3----->KCl2 +3O2

the equation is balanced

How many grams of O2 will be formed from 3.76 grams of KClO3?

How many grams of KClO3 are needed to make 30.0 grams of KCl?

How many grams of KCl will be formed from 2.73 grams of KClO3?

2KClO3----->2KCl +3O2

I meant to have the equation like this

To answer these questions, we need to use stoichiometry, which is a way to relate the amounts of different substances involved in a chemical reaction. In this case, we will be using the balanced equation:

2KClO3 -----> KCl2 + 3O2

Question 1: How many grams of O2 will be formed from 3.76 grams of KClO3?

To solve this question, we need to use the stoichiometric ratio between KClO3 and O2 from the balanced equation. From the equation, we see that for every 2 moles of KClO3, we get 3 moles of O2.

1. Convert the grams of KClO3 to moles. To do this, we can use the molar mass of KClO3, which is 122.55 g/mol:
moles of KClO3 = 3.76 g / 122.55 g/mol

2. Use the stoichiometric ratio to calculate the moles of O2 produced:
moles of O2 = (moles of KClO3) x (3 moles O2 / 2 moles KClO3)

3. Finally, convert the moles of O2 to grams using the molar mass of O2, which is 32.00 g/mol:
grams of O2 = (moles of O2) x (32.00 g/mol)

Question 2: How many grams of KClO3 are needed to make 30.0 grams of KCl?

In this question, we need to use the stoichiometric ratio between KClO3 and KCl. From the balanced equation, we know that 2 moles of KClO3 produce 1 mole of KCl.

1. Convert the grams of KCl to moles. To do this, we can use the molar mass of KCl, which is 74.55 g/mol:
moles of KCl = 30.0 g / 74.55 g/mol

2. Use the stoichiometric ratio to calculate the moles of KClO3 needed:
moles of KClO3 = (moles of KCl) x (2 moles KClO3 / 1 mole KCl)

3. Finally, convert the moles of KClO3 to grams using the molar mass of KClO3, which is 122.55 g/mol:
grams of KClO3 = (moles of KClO3) x (122.55 g/mol)

Question 3: How many grams of KCl will be formed from 2.73 grams of KClO3?

Again, we need to use the stoichiometric ratio between KClO3 and KCl from the balanced equation. From the equation, we see that 2 moles of KClO3 produce 1 mole of KCl.

1. Convert the grams of KClO3 to moles using the molar mass of KClO3:
moles of KClO3 = 2.73 g / 122.55 g/mol

2. Use the stoichiometric ratio to calculate the moles of KCl produced:
moles of KCl = (moles of KClO3) x (1 mole KCl / 2 moles KClO3)

3. Finally, convert the moles of KCl to grams using the molar mass of KCl, which is 74.55 g/mol:
grams of KCl = (moles of KCl) x (74.55 g/mol)

By following these steps, you can calculate the grams of O2, KClO3, and KCl involved in these reactions based on the given amounts.

It is NOT balanced

2 K on left, 1 K on right
maybe
2 KClO3----->2 KCl +3 O2
?
get that right first, then find grams per mol for everything

2KClO3----->KCl2 +3O2

the equation is balanced
No, wrong equation. You NEVER, NEVER, NEVER, NEVER, EVER, balance an equation by changing the subscripts. You ALWAYS change the coefficient.
2KClO3 ==> 2KCl + 3O2


How many grams of O2 will be formed from 3.76 grams of KClO3?
mols KClO3 = grams/molar mass = 3.76/122.5 = approx 0.03. Convert mols KClO3 to mols O2 this way.
0.3 mols KClO3 x (3 mols O2/2 mols KClO3) = approx 0.3 x 3/2 = 0.45.
grams O2 = mols O2 x molar mass O2 = ?


How many grams of KClO3 are needed to make 30.0 grams of KCl?
Use the same process to calculate grams KClO3 to make 30.0 g KCl.
Post or work if you get stuck.
Use the same process to do the last part also.


How many grams of KCl will be formed from 2.73 grams of KClO3?