Write a molecular, a complete, and a net ionic equation for the following reactions in aqueous solutions. All equations must be balanced.
a. HI(aq) and Ba(OH)2(aq)
b. HBr(aq) and LiOH(aq)
c. HCHO2(aq), a weak acid, and NaOH
d. HBr(aq) and K2SO3(aq)
a. Molecular equation: 2HI(aq) + Ba(OH)2(aq) → 2H2O(l) + BaI2(aq)
Complete ionic equation: 2H+(aq) + 2I^-(aq) + Ba2+(aq) + 2OH^-(aq) → 2H2O(l) + Ba2+(aq) + 2I^-(aq)
Net ionic equation: 2H+(aq) + 2OH^-(aq) → 2H2O(l)
b. Molecular equation: 2HBr(aq) + 2LiOH(aq) → 2H2O(l) + 2LiBr(aq)
Complete ionic equation: 2H+(aq) + 2Br^-(aq) + 2Li+(aq) + 2OH^-(aq) → 2H2O(l) + 2Li+(aq) + 2Br^-(aq)
Net ionic equation: 2H+(aq) + 2OH^-(aq) → 2H2O(l)
c. Molecular equation: HCHO2(aq) + NaOH(aq) → H2O(l) + NaCHO2(aq)
Complete ionic equation: H+(aq) + CHO2^-(aq) + Na+(aq) + OH^-(aq) → H2O(l) + Na+(aq) + CHO2^-(aq)
Net ionic equation: H+(aq) + OH^-(aq) → H2O(l)
d. Molecular equation: 2HBr(aq) + K2SO3(aq) → 2KBr(aq) + H2SO3(aq)
Complete ionic equation: 2H+(aq) + 2Br^-(aq) + 2K+(aq) + SO3^2-(aq) → 2K+(aq) + 2Br^-(aq) + H2SO3(aq)
Net ionic equation: 2H+(aq) + SO3^2-(aq) → H2SO3(aq)
a. HI(aq) and Ba(OH)2(aq)
Molecular equation:
2HI(aq) + Ba(OH)2(aq) → BaI2(aq) + 2H2O(l)
Complete ionic equation:
2H+(aq) + 2I-(aq) + Ba2+(aq) + 2OH-(aq) → BaI2(aq) + 2H2O(l)
Net ionic equation:
2H+(aq) + 2OH-(aq) → 2H2O(l)
b. HBr(aq) and LiOH(aq)
Molecular equation:
HBr(aq) + LiOH(aq) → LiBr(aq) + H2O(l)
Complete ionic equation:
H+(aq) + Br-(aq) + Li+(aq) + OH-(aq) → Li+(aq) + Br-(aq) + H2O(l)
Net ionic equation:
H+(aq) + OH-(aq) → H2O(l)
c. HCHO2(aq), a weak acid, and NaOH
Molecular equation:
HCHO2(aq) + NaOH(aq) → NaCHO2(aq) + H2O(l)
Complete ionic equation:
H+(aq) + CHO2-(aq) + Na+(aq) + OH-(aq) → Na+(aq) + CHO2-(aq) + H2O(l)
Net ionic equation:
H+(aq) + OH-(aq) → H2O(l)
d. HBr(aq) and K2SO3(aq)
Molecular equation:
2HBr(aq) + K2SO3(aq) → 2KBr(aq) + H2SO3(aq)
Complete ionic equation:
2H+(aq) + 2Br-(aq) + 2K+(aq) + SO3^2-(aq) → 2K+(aq) + 2Br-(aq) + H2SO3(aq)
Net ionic equation:
H+(aq) + SO3^2-(aq) → H2SO3(aq)
To write a molecular, complete, and net ionic equation for each reaction, we need to first identify the products formed when the reactants are combined. Then, we will balance the equations.
a. HI(aq) and Ba(OH)2(aq)
The reactants are HI (Hydroiodic acid) and Ba(OH)2 (Barium hydroxide).
The products formed are H2O (water) and BaI2 (Barium iodide).
Molecular Equation:
HI(aq) + Ba(OH)2(aq) --> BaI2(aq) + H2O(l)
Complete Ionic Equation:
H+(aq) + I-(aq) + Ba2+(aq) + 2OH-(aq) --> BaI2(aq) + 2H2O(l)
Net Ionic Equation:
H+(aq) + OH-(aq) --> H2O(l)
b. HBr(aq) and LiOH(aq)
The reactants are HBr (Hydrobromic acid) and LiOH (Lithium hydroxide).
The products formed are H2O (water) and LiBr (Lithium bromide).
Molecular Equation:
HBr(aq) + LiOH(aq) --> LiBr(aq) + H2O(l)
Complete Ionic Equation:
H+(aq) + Br-(aq) + Li+(aq) + OH-(aq) --> LiBr(aq) + H2O(l)
Net Ionic Equation:
H+(aq) + OH-(aq) --> H2O(l)
c. HCHO2(aq), a weak acid, and NaOH(aq)
The reactants are HCHO2 (Formic acid) and NaOH (Sodium hydroxide).
The products formed are H2O (water) and NaCHO2 (Sodium formate).
Molecular Equation:
HCHO2(aq) + NaOH(aq) --> NaCHO2(aq) + H2O(l)
Complete Ionic Equation:
HCHO2(aq) + Na+(aq) + OH-(aq) --> NaCHO2(aq) + H2O(l)
Net Ionic Equation:
HCHO2(aq) + OH-(aq) --> H2O(l)
d. HBr(aq) and K2SO3(aq)
The reactants are HBr (Hydrobromic acid) and K2SO3 (Potassium sulfite).
The products formed are H2O (water) and KBr (Potassium bromide).
Molecular Equation:
HBr(aq) + K2SO3(aq) --> KBr(aq) + H2O(l) + SO2(g)
Complete Ionic Equation:
H+(aq) + Br-(aq) + 2K+(aq) + SO3^(2-)(aq) --> KBr(aq) + H2O(l) + SO2(g)
Net Ionic Equation:
H+(aq) + Br-(aq) --> H2O(l)
After writing the equations, it is important to balance them by adjusting the coefficients in front of each chemical formula.
I assume you know how to do parts of this and I'm not about to duplicate work you should know how to do. I'll leave the balanced molecular equation for you. Then tell me what you don't understand about the rest of it. Its ridiculous that I sit here at bedtime and look for all those ()aq ^- ^+ etc.
I will write the net ionic equation for you. You do all that leads up to that.
a. HI(aq) and Ba(OH)2(aq)
b. HBr(aq) and LiOH(aq)
c. HCHO2(aq), a weak acid, and NaOH
d. HBr(aq) and K2SO3(aq)
a. 2H^+(aq) + 2OH^-(aq) ==> 2H2O(l)
b. H^+(aq) + OH^-(aq) ==> H2O(l)
c. HCHO2(aq) +OH^-(aq) ==> H2O(l) + [CHO2]^-(aq)
d. 2H^+(aq) + [SO3]^2-(aq) ==> H2SO3(aq)
NOTE: Some don't consider H2SO3 a compound arguing it is SO2 + H2O and some may argue that it is (l) and not (aq) but I'm assuming this is a lower level question.
I will be happy to answer specific questions but all of the other typing is too much work to do; however I shall be happy to help you through rough spots.