Jennifer got a box of chocolates. The box is a right triangular prism shaped box. It is 7 inches long, and the triangular base measures 3in x 4in x 5in. What is the surface area of the box of chocolates
You already indicate the triangular base, so how could it be 7 inches "long"?
Proof read your posts.
Notice that the base is a right-angled triangle, since 3^2 + 4^2 = 5^2
the area of the base is (1/2)(3)(4) = 6 in^2
Remember you have the top also, same area
Then you have 3 long rectangles, you know the length of each is 7 and the widths are 3, 4, and 5
To find the surface area of the box of chocolates, you need to calculate the sum of the areas of all the faces.
First, let's find the area of the triangular base. The formula to find the area of a triangle is 1/2 * base * height. In this case, the base is 4 inches and the height is 3 inches. Therefore, the area of the triangular base is 1/2 * 4in * 3in = 6 square inches.
Next, let's find the area of the other faces. Since the box is a right triangular prism, it has three rectangular faces. Each of these faces has a length of 7 inches and a width equal to the perimeter of the triangular base.
To find the perimeter of the triangular base, we add all three sides together: 3in + 4in + 5in = 12in.
Now, calculate the area of each rectangular face by multiplying the length by the width: 7in * 12in = 84 square inches.
Since there are three identical rectangular faces on the box, the total area of all the rectangular faces is 3 * 84in² = 252 square inches.
Finally, add the area of the triangular base and the area of the rectangular faces to get the total surface area: 6in² + 252in² = 258 square inches.
Therefore, the surface area of the box of chocolates is 258 square inches.