how would this multiply out

(1/cosө) (Sin^2ө + cos^2ө/cosө * sinө)

well first of all Sin^2ө + cos^2ө = 1

i know but how do you multiply it out?

To multiply out the expression (1/cosө) (Sin^2ө + cos^2ө/cosө * sinө), let's break down the steps:

Step 1: Simplify the expression within the second set of parentheses.
- The expression Sin^2ө + cos^2ө represents the identity of trigonometry that states: sin^2θ + cos^2θ = 1. We can substitute the expression with 1.
- After substitution, the expression becomes (1/cosө) (1/cosө * sinө).

Step 2: Multiply the expressions.
- Multiply the numerators: 1 * 1 * sinө = sinө.
- Multiply the denominators: cosө * cosө = cos^2ө.
- The expression becomes sinө/cos^2ө.

Therefore, the expression (1/cosө) (Sin^2ө + cos^2ө/cosө * sinө) simplifies to sinө/cos^2ө.