A pass code consists of 4 digits, 2 numbers followed by 2 letters and the digits cannot be repeated but the letters can, how many codes are possible
10*9 * 26^2 = ____
To find the number of possible codes, we need to consider the options for each part of the passcode.
For the first digit, we have 10 options (0-9).
For the second digit, we have 9 options, as we cannot choose the same digit as the first one.
For the first letter, we have 26 options (A-Z).
For the second letter, we also have 26 options.
To find the total number of possibilities, we need to multiply the number of options for each part together:
10 options for the first digit x 9 options for the second digit x 26 options for the first letter x 26 options for the second letter
So the total number of possible codes is 10 x 9 x 26 x 26 = 60,840.